LEETCODE Weekly Contest 365 SOLUTION || Maximum Value of an Ordered Triplet II SOLUTION || JAVA ||c+

LEETCODE Weekly Contest 365 ALL SOLUTION || Maximum Value of an Ordered Triplet II SOLUTION || JAVA ||c++

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Weekly Contest 365 solution

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100088. Maximum Value of an Ordered Triplet I
100088. Maximum Value of an Ordered Triplet I
100088. Maximum Value of an Ordered Triplet I

100086. Maximum Value of an Ordered Triplet II
100086. Maximum Value of an Ordered Triplet II
100086. Maximum Value of an Ordered Triplet II

Maximum Value of an Ordered Triplet I SOLUTION
Maximum Value of an Ordered Triplet I SOLUTION IN C++
Maximum Value of an Ordered Triplet I SOLUTION IN JAVA
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Maximum Value of an Ordered Triplet I SOLUTION IN C

Maximum Value of an Ordered Triplet II SOLUTION
Maximum Value of an Ordered Triplet II SOLUTION IN C++
Maximum Value of an Ordered Triplet II SOLUTION IN JAVA
Maximum Value of an Ordered Triplet II SOLUTION IN PYTHON
Maximum Value of an Ordered Triplet II SOLUTION IN C

Minimum Size Subarray in Infinite Array solution
Minimum Size Subarray in Infinite Array in comment box

100076. Minimum Size Subarray in Infinite Array IN JAVA
100076. Minimum Size Subarray in Infinite Array IN C++



You are given a 0-indexed integer array nums.

Return the maximum value over all triplets of indices (i, j, k) such that If all such triplets have a negative value, return 0.

The value of a triplet of indices (i, j, k) is equal to (nums[i] - nums[j]) * nums[k].



Example 1:

Input: nums = [12,6,1,2,7]
Output: 77
Explanation: The value of the triplet (0, 2, 4) is (nums[0] - nums[2]) * nums[4] = 77.
It can be shown that there are no ordered triplets of indices with a value greater than 77.
Example 2:

Input: nums = [1,10,3,4,19]
Output: 133
Explanation: The value of the triplet (1, 2, 4) is (nums[1] - nums[2]) * nums[4] = 133.
It can be shown that there are no ordered triplets of indices with a value greater than 133.
Example 3:

Input: nums = [1,2,3]
Output: 0
Explanation: The only ordered triplet of indices (0, 1, 2) has a negative value of (nums[0] - nums[1]) * nums[2] = -3. Hence, the answer would be 0.

Count Visited Nodes in a Directed Graph

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